0=7x^2-567

Solution for 0=7x^2-567 equation:

0=7x^2-567

We move all terms to the left:

0-(7x^2-567)=0

We add all the numbers together, and all the variables

-(7x^2-567)=0

We get rid of parentheses

-7x^2+567=0

a = -7; b = 0; c = +567;
Δ = b2-4ac
Δ = 02-4·(-7)·567
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*-7}=\frac{-126}{-14}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*-7}=\frac{126}{-14}
=-9
$